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प्रश्न
Fill in the blanks in the table.
| Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
| ...... | 6% | 4 years | 1200 | ...... |
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उत्तर
| Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
| 5000 | 6% | 4 years | 1200 | 6200 |
Explanation:
Given:
Total interest (I) = 1200 rupess
Rate of interest (R) = 6%
Time (T) = 4 years
Formula:
Principal (P) = `("I"xx100)/("R"xx"T")`
Solution:
= `(1200xx100)/(6xx4)`
= 5000 rupees
Total Amount = P + I
= 5000 + 1200
= 6200 rupees
संबंधित प्रश्न
A page from the savings bank account of Mrs Ravi is given below.
| Date | Particulars | Withdrawal (Rs.) |
Deposit (Rs.) | Balance (Rs.) |
| April 3rd 2006 | B/F | 6000 | ||
| April 7th | By cash | 2300 | 8300 | |
| April 15th | By cheque | 3500 | 11800 | |
| May 20th | To self | 4200 | 7600 | |
| June 10th | By cash | 5800 | 13400 | |
| June 15th | To self | 3100 | 10300 | |
| August 13th | By cheque | 1000 | 11300 | |
| August 25th | To self | 7400 | 3900 | |
| September 6th 2006 |
By cash | 2000 | 5900 |
She closed the account on 30th September 2006. Calculate the interest Mrs Ravi earned
at the end of 30th September 2006 at 4.5% per annum interest. Hence, find the
amount she receives on closing the account.
Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets Rs. 1200 as interest at the time of maturity, find:
- the monthly instalment.
- the amount of maturity.
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Make the entries in his passbook
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