Question

Figure 6 below shows an electric circuit.

Apply Kirchhoff’s laws to calculate:

1. current ‘I’ flowing through the 2Ω resistor.
2. emf of the cell ‘E’.

Answer 1

a. Applying kirchhoff’s junction rule at the point Q,

I + 3 = 4

⇒ I = 4 − 3 

⇒ I = 1 A

b. Applying Kirchhoff’s voltage rule in the loop SQRS, we get,

E = (2 × 1 + 4 × 1)

= 6 V