Advertisements
Advertisements
प्रश्न
Factorize: `a^2 x^2 + (ax^2 + 1)x + a`
Advertisements
उत्तर
We Multiply x (ax2 +1) = ax3 + x
= a2 x2 + ax3 + x + a
Taking common ax2 in (a2 x2 + ax3 ) and 1 in ( x + a)
= ax2 (a + x) +1( x + a)
= ax2 (a + x) +1(a + x)
Taking (a + x ) common in both the terms
= (a + x)(ax2 +1)
∴ a2 x2 + (ax2 +1) x + a = (a + x)(ax2 +1)
APPEARS IN
संबंधित प्रश्न
Factorize `x^2 - sqrt3x - 6`
Factorize 125x3 - 27 y3 - 225x2 y +135xy2
The factors of x3 − 7x + 6 are
Separate monomials, binomials, trinomials and polynomials from the following algebraic expressions :
8 − 3x, xy2, 3y2 − 5y + 8, 9x − 3x2 + 15x3 − 7,
3x × 5y, 3x ÷ 5y, 2y ÷ 7 + 3x − 7 and 4 − ax2 + bx + y
Divide: 8x + 24 by 4
Divide: 2m3n5 by - mn
Express the following as an algebraic expression:
The sum of x and y minus m.
Solve the following equation.
4(x + 12) = 8
Write the coefficient of x2 and x in the following polynomials
πx2 – x + 2
Will the value of 11x for x = –5 be greater than 11 or less than 11? Explain.
