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प्रश्न
Factorise the following:
42a2bc4 – 56a3b2c3
बेरीज
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उत्तर
Given expression: 42a2bc4 – 56a3b2c3
Step-wise calculation:
1. Find the highest common factor (HCF) of the numerical coefficients 42 and 56:
- HCF of 42 and 56 is 14.
2. Find the common variables with the lowest powers in both terms:
- For a2 and a3, the lower power is a2.
- For b and b2, the lower power is b.
- For c4 and c3, the lower power is c3.
3. Take out the common factor 14a2bc3.
4. Divide each term by 14a2bc3:
- 42a2bc4 ÷ 14a2bc3 = 3c
- 56a3b2c3 ÷ 14a2bc3 = 4ab
5. Write the factored form as 14a2bc3(3c – 4ab).
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