हिंदी

Factorise the following: 42a^2bc^4 – 56a^3b^2c^3 - Mathematics

Advertisements
Advertisements

प्रश्न

Factorise the following:

42a2bc4 – 56a3b2c3

योग
Advertisements

उत्तर

Given expression: 42a2bc4 – 56a3b2c3

Step-wise calculation:

1. Find the highest common factor (HCF) of the numerical coefficients 42 and 56:

  • HCF of 42 and 56 is 14.

2. Find the common variables with the lowest powers in both terms:

  • For a2 and a3, the lower power is a2.
  • For b and b2, the lower power is b.
  • For c4 and c3, the lower power is c3.

3. Take out the common factor 14a2bc3.

4. Divide each term by 14a2bc3:

  • 42a2bc4 ÷ 14a2bc3 = 3c
  • 56a3b2c3 ÷ 14a2bc3 = 4ab

5. Write the factored form as 14a2bc3(3c – 4ab).

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Factorisation - Exercise 4A [पृष्ठ ७८]

APPEARS IN

नूतन Mathematics [English] Class 9 ICSE
अध्याय 4 Factorisation
Exercise 4A | Q 7. | पृष्ठ ७८
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×