मराठी

F(X) = X 2 + 2 X , X > 0 . - Mathematics

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प्रश्न

f(x) =\[\frac{x}{2} + \frac{2}{x} , x > 0\] .

बेरीज
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उत्तर

\[\text { Given }: \hspace{0.167em} f\left( x \right) = \frac{x}{2} + \frac{2}{x}\]

\[ \Rightarrow f'\left( x \right) = \frac{1}{2} - \frac{2}{x^2}\]

\[\text { For the local maxima or minima, we must have }\]

\[f'\left( x \right) = 0\]

\[ \Rightarrow \frac{1}{2} - \frac{2}{x^2} = 0\]

\[ \Rightarrow \frac{1}{2} = \frac{2}{x^2}\]

\[ \Rightarrow x^2 = \pm 2\]

Since x > 0,  f '(x) changes from negative to positive when x increases through 2. So, x = 2 is a point of local minima.

The local minimum value of  f (x) at x = 2 is given by \[\frac{2}{2} + \frac{2}{2} = 2\]

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पाठ 18: Maxima and Minima - Exercise 18.2 [पृष्ठ १६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 18 Maxima and Minima
Exercise 18.2 | Q 14 | पृष्ठ १६

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