Advertisements
Advertisements
प्रश्न
f(x) = 2x3 − 9x2 + x + 12, g(x) = 3 − 2x
Advertisements
उत्तर
It is given that f(x) = 2x3 − 9x2 + x + 12 and g(x) = (3 − 2x)
By factor theorem, (3 − 2x) is the factor of f(x), if f(3/2)= 0
Therefore,
In order to prove that (3 − 2x) is a factor of f(x). It is sufficient to show that `f(3/2) = 0`
Now,
`f(3/2) = 2(3/2)^3 -9(3/2)^2 +(3/2) + 12`
` = 27/4 - 81/4 + 3/2 + 12`
` = 54 / 4 + 3/2 + 12`
` = -27/2 + 3/2 +12`
` = -12 + 12`
`= 0`
Hence, (3 − 2x), is the factor of polynomial f(x).
APPEARS IN
संबंधित प्रश्न
f(x) = 2x4 − 6x3 + 2x2 − x + 2, g(x) = x + 2
2y3 − 5y2 − 19y + 42
Write the remainder when the polynomialf(x) = x3 + x2 − 3x + 2 is divided by x + 1.
If x + 1 is a factor of x3 + a, then write the value of a.
If x51 + 51 is divided by x + 1, the remainder is
Factorise the following:
(p – q)2 – 6(p – q) – 16
Factorise the following:
m2 + 2mn – 24n2
Which of the following has x – 1 as a factor?
If (x + 5) and (x – 3) are the factors of ax2 + bx + c, then values of a, b and c are
Factorise:
x3 – 6x2 + 11x – 6
