Advertisements
Advertisements
प्रश्न
Let f(x) be a polynomial such that \[f\left( - \frac{1}{2} \right)\] = 0, then a factor of f(x) is
पर्याय
2x − 1
2x + 1
x − 1
x +1
Advertisements
उत्तर
Let f(x) be a polynomial such that `f(-1/2) = 0`
i.e., `x + 1/2 = 0` is a factor.
On rearranging `x+ 1/2 = 0` can be written as (2x + 1) = 0
Thus, (2x + 1)is a factor of f(x).
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`sqrt3x-7`
Find the remainder when x3 + 3x2 + 3x + 1 is divided by \[x + \pi\] .
If x − 2 is a factor of the following two polynomials, find the values of a in each case x3 − 2ax2 + ax − 1.
What must be added to x3 − 3x2 − 12x + 19 so that the result is exactly divisibly by x2 + x - 6 ?
x3 − 23x2 + 142x − 120
x4 + 10x3 + 35x2 + 50x + 24
If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then k =
If x140 + 2x151 + k is divisible by x + 1, then the value of k is
When x3 − 2x2 + ax − b is divided by x2 − 2x − 3, the remainder is x − 6. The values of a and b are respectively
Factorise the following:
a4 – 3a2 + 2
