Advertisements
Advertisements
प्रश्न
Express the following as the product of sine and cosine.
sin 6θ – sin 2θ
बेरीज
Advertisements
उत्तर
sin 6θ – sin 2θ
`= 2 cos ((6theta + 2theta)/2) cos ((6theta - 2theta)/2)` ...`[∵ sin "C" - sin "D" = 2 cos (("C + D")/2) cos (("C - D")/2)]`
= 2 cos `((8theta)/2) sin ((4theta)/2)`
= 2 cos 4θ sin 2θ
shaalaa.com
Transformation Formulae
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Trigonometry - Exercise 4.3 [पृष्ठ ८८]
APPEARS IN
संबंधित प्रश्न
Prove that:
sin 38° + sin 22° = sin 82°
Prove that:
sin 80° − cos 70° = cos 50°
Prove that:
\[\frac{\sin A + \sin B}{\sin A - \sin B} = \tan \left( \frac{A + B}{2} \right) \cot \left( \frac{A - B}{2} \right)\]
Prove that:
\[\frac{\sin 5A - \sin 7A + \sin 8A - \sin 4A}{\cos 4A + \cos 7A - \cos 5A - \cos 8A} = \cot 6A\]
Prove that:
\[\frac{\sin 5A \cos 2A - \sin 6A \cos A}{\sin A \sin 2A - \cos 2A \cos 3A} = \tan A\]
If cos (α + β) sin (γ + δ) = cos (α − β) sin (γ − δ), prove that cot α cot β cot γ = cot δ
cos 40° + cos 80° + cos 160° + cos 240° =
If sin 2 θ + sin 2 ϕ = \[\frac{1}{2}\] and cos 2 θ + cos 2 ϕ = \[\frac{3}{2}\], then cos2 (θ − ϕ) =
Express the following as the product of sine and cosine.
sin A + sin 2A
Prove that:
tan 20° tan 40° tan 80° = `sqrt3`.
