Advertisements
Advertisements
प्रश्न
Express the following as the product of sine and cosine.
sin 6θ – sin 2θ
योग
Advertisements
उत्तर
sin 6θ – sin 2θ
`= 2 cos ((6theta + 2theta)/2) cos ((6theta - 2theta)/2)` ...`[∵ sin "C" - sin "D" = 2 cos (("C + D")/2) cos (("C - D")/2)]`
= 2 cos `((8theta)/2) sin ((4theta)/2)`
= 2 cos 4θ sin 2θ
shaalaa.com
Transformation Formulae
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Trigonometry - Exercise 4.3 [पृष्ठ ८८]
APPEARS IN
संबंधित प्रश्न
Show that :
\[\sin 50^\circ \cos 85^\circ = \frac{1 - \sqrt{2} \sin 35^\circ}{2\sqrt{2}}\]
Prove that:
cos 20° cos 40° cos 80° = \[\frac{1}{8}\]
Express each of the following as the product of sines and cosines:
sin 2x + cos 4x
Prove that:
sin 38° + sin 22° = sin 82°
Prove that:
sin 80° − cos 70° = cos 50°
Prove that:
\[\cos\left( \frac{\pi}{4} + x \right) + \cos\left( \frac{\pi}{4} - x \right) = \sqrt{2} \cos x\]
Write the value of \[\frac{\sin A + \sin 3A}{\cos A + \cos 3A}\]
cos 35° + cos 85° + cos 155° =
Express the following as the sum or difference of sine or cosine:
`cos (7"A")/3 sin (5"A")/3`
If secx cos5x + 1 = 0, where 0 < x ≤ `pi/2`, then find the value of x.
