Advertisements
Advertisements
प्रश्न
Express the following as the product of sine and cosine.
sin 6θ – sin 2θ
Advertisements
उत्तर
sin 6θ – sin 2θ
`= 2 cos ((6theta + 2theta)/2) cos ((6theta - 2theta)/2)` ...`[∵ sin "C" - sin "D" = 2 cos (("C + D")/2) cos (("C - D")/2)]`
= 2 cos `((8theta)/2) sin ((4theta)/2)`
= 2 cos 4θ sin 2θ
APPEARS IN
संबंधित प्रश्न
Express each of the following as the product of sines and cosines:
sin 2x + cos 4x
Prove that:
sin 23° + sin 37° = cos 7°
Prove that:
sin 3A + sin 2A − sin A = 4 sin A cos \[\frac{A}{2}\] \[\frac{3A}{2}\]
Prove that:
Prove that:
cos (A + B + C) + cos (A − B + C) + cos (A + B − C) + cos (− A + B + C) = 4 cos A cos Bcos C
If sin α + sin β = a and cos α − cos β = b, then tan \[\frac{\alpha - \beta}{2}\]=
The value of sin 50° − sin 70° + sin 10° is equal to
If \[\tan\alpha = \frac{x}{x + 1}\] and
Prove that:
tan 20° tan 40° tan 80° = `sqrt3`.
Prove that:
`(cos 2"A" - cos 3"A")/(sin "2A" + sin "3A") = tan "A"/2`
