Advertisements
Advertisements
प्रश्न
Express the following in terms of angles between 0° and 45°:
cosec68° + cot72°
Advertisements
उत्तर
cosec68° + cot72°
= cosec(90 - 22)° + cot(90 -18)°
= sec22° + tan18°
संबंधित प्रश्न
If the angle θ = -60° , find the value of sinθ .
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
Evaluate.
`cos^2 26^@+cos65^@sin26^@+tan36^@/cot54^@`
Evaluate:
`2(tan35^@/cot55^@)^2 + (cot55^@/tan35^@)^2 - 3(sec40^@/(cosec50^@))`
Prove that:
tan (55° - A) - cot (35° + A)
Find A, if 0° ≤ A ≤ 90° and 4 sin2 A – 3 = 0
If tanθ = 2, find the values of other trigonometric ratios.
If \[\tan \theta = \frac{1}{\sqrt{7}}, \text{ then } \frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta} =\]
Prove that:
(sin θ + 1 + cos θ) (sin θ − 1 + cos θ) . sec θ cosec θ = 2
The value of the expression (cos2 23° – sin2 67°) is positive.
