Advertisements
Advertisements
प्रश्न
Explain why (or how) A violin note and sitar note may have the same frequency, yet we can distinguish between the two notes,
Advertisements
उत्तर १
The overtones produced by a sitar and a violin, and the strengths of these overtones, are different. Hence, one can distinguish between the notes produced by a sitar and a violin even if they have the same frequency of vibration.
उत्तर २
The quality of a violin note is different from the quality of sitar. Therefore, they emit different harmonics which can be observed by human ear and used to differentiate between the two notes.
संबंधित प्रश्न
In Doppler effect of light, the term “red shift” is used for ______.
(A) frequency increase
(B) frequency decrease
(C) wavelength decrease
(D) frequency and wavelength increase
Apparent frequency of the sound heard by a listener is less than the actual frequency of sound emitted by source. In this case _______.
(A) listener moves towards source
(B) source moves towards listener
(C) listener moves away from the source.
(D) source and listener move towards each other.
A set of 8 tuning forks is arranged in a series of increasing order of frequencies. Each fork gives 4 beats per second with the next one and the frequency of last fork is twice that of the first. Calculate the frequencies of the first and the last fork.
If two tuning forks A and B are sounded together, they produce 4 beats per second. When A is slightly loaded with wax, they produce 2 beats when sounded again. The frequency of A is 256 Hz. The frequency of B will be ______
Two waves of wavelength 2 m and 2.02 m, with the same speed superimpose to produce 2 beats per second. The speed of each wave is ____________.
For formation of beats, two sound notes must have ______.
A set of 25 tuning forks is arranged in order of decreasing frequencies. Each fork produces 3 beats with succeeding one. If the first fork is octave of last, then the frequency of 1st and 15th fork in Hz is ______.
Two tuning forks have frequencies 380 Hz and 384 Hz respectively. When they are sounded together, maximum sound is heard. How long will it take to hear the minimum sound?
A set of 56 tuning forks are arranged in series of increasing frequencies. If each fork gives 4 beats with preceding one and the frequency of the last is twice than than that of first, then frequency of the first fork is ____________.
A pipe open at both ends has a length of 1m. The air column in the pipe can not resonate for a frequency (Neglect end correction, speed of sound in air = 340 m/s)
Two wires are producing fundamental notes of the same frequency. Change in which of the following factors of one wire will NOT produce beats between them?
The frequency of two tuning forks A and B are 1.5% more and 2.5% less than that of the tuning fork C. When A and B are sounded together, 12 beats are produced in 1 second. The frequency of tuning fork C is ______
A tuning fork A, marked 512 Hz, produces 5 beats per second, where sounded with another unmarked tuning fork B. If B is loaded with wax the number of beats is again 5 per second. What is the frequency of the tuning fork B when not loaded?
Wire having tension 225 N produces six beats per second when it is tuned with a fork. When tension changes to 256 N, it is tuned with the same fork, the number of beats remain unchanged. The frequency of the fork will be ______.
If beat frequency is 2 Hz, what is the time interval between success waxings?
A sonometer wire under a tension of 40 N vibrates in unison with a tuning fork of frequency 384 Hz. Find the beat frequency when the tension in the wire is reduced by 0.21 N.
