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प्रश्न
Explain in brief – Goldstein’s experiment which led to the discovery of the proton.
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उत्तर
Discovery of – Protons
- Discovery – Constituent of positive rays i.e. particles that contain – protons.
Experiment:
- Goldstein used a modified cathode ray tube with a perforated cathode.
- He observed a new type of rays produced from the anode passing through the holes of the perforated cathode. These rays were called anode rays.
Conclusion:
- Anode rays or positive rays consist of positively charged particles now called – protons.
- The positive rays were affected by electric & magnetic fields but – in a direction opposite to that of cathode rays.
- Thus with the discovery of the positive particles – proton was initiated.
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संबंधित प्रश्न
Fill in the blank
The outermost shell of an atom is known as............................
Give the following a suitable word/phrase.
Protons and neutrons present in the nucleus.
Name three fundamental particles of the atom. Give the symbol with charge, on each particle.
FILL IN THE BLANK
Gases become good conductors of electricity under ........ (low/high) pressure and .............. (low/high) voltage electrical discharge.
Tick the most appropriate answer.
How many times is a proton heavier than an electron?
- 1500
- 1800
- 1840
- none of these
Draw the electronic configuration of the following elements clearly stating the number of neutrons and protons in their nucleus.
a. Beryllium b. Silicon
c. Chlorine d. Aluminium
e. Nitrogen
Name the negatively charged particle present in the atoms of all the elements.
State its one drawback of Rutherford’s atomic model.
With reference to the discovery of the structure of an atom, explain in brief – William Crookes experiment for the discovery of cathode rays, followed by – J.J. Thomsons experiment pertaining to the constituents of the cathode rays. State which sub-atomic particle was discovered from his experiment.
Select the correct answer from the choice in the bracket to complete the sentence:
Magnesium atom with electronic configuration 2, 8, 2 achieves stable electronic configuration by losing two electrons, thereby achieving stable electronic configuration of the nearest noble gas _______.
