Advertisements
Advertisements
प्रश्न
Explain briefly, using a proper diagram, the difference in behaviour of a conductor and a dielectric in the presence of external electric field.
Advertisements
उत्तर
In conductor there is equal amount of induced electric field inside conductor, due to which net electric field is zero.
In case of dielectric, electric field induced inside in less than external electric field.
So there is net electric field inside dielectric.
APPEARS IN
संबंधित प्रश्न
Distinguish with the help of a suitable diagram, the difference in the behaviour of a conductor and a dielectric placed in an external electric field.
Write a relation for polarisation `vecP`of a dielectric material in the presence of an external electric field `vecE .`
Define the terms polarization of a dielectric and write its relation with susceptibility.
Two metal plates having charges Q, −Q face each other at some separation and are dipped into an oil tank. If the oil is pumped out, the electric field between the plates will
A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is Q and the magnitude of the induced charge on each surface of the dielectric is Q'.
A parallel-plate capacitor having plate area 400 cm2 and separation between the plates 1⋅0 mm is connected to a power supply of 100 V. A dielectric slab of thickness 0⋅5 mm and dielectric constant 5⋅0 is inserted into the gap. (a) Find the increase in electrostatic energy. (b) If the power supply is now disconnected and the dielectric slab is taken out, find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?
Explain briefly, using a proper diagram, the difference in the behavior of a conductor and a dielectric in the presence of an external electric field.
An isolated parallel plate capacitor is maintained at a certain potential difference. When a 3 mm thick slab is introduced between the plates, in order to maintain the same potential difference the distance between the plates is increased by 2.4 mm. The dielectric constant of the slab will be ______.
