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प्रश्न
Explain the basic differences between the construction and working of a telescope and a microscope
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उत्तर
| Telescope | Microscope |
| It is used for observing distant images of heavenly bodies such as stars and planets. |
It is used for observing magnifying |
| The objective lens has a large focal length and large aperture |
The objective lens has a small focal length and short aperture. |
| The eye lens used has small focal length and small aperture. | The eye lens used has moderate focal length and large aperture. |
| The distance between the objective lens and eye lens is adjusted to focus the object situated at infinity. | The objective and eye lens are kept at a fixed distance apart, whereas the distance of the objective lens from the object is adjusted to focus an object. |
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संबंधित प्रश्न
If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens ? the diameter of the moon is 3.48 × 106 m and the radius of lunar orbit is 3.8 × 108m.
Draw a labelled ray diagram showing the formation of a final image by a compound microscope at least distance of distinct vision
Why must both the objective and the eyepiece of a compound microscope have short focal lengths?
An angular magnification (magnifying power) of 30X is desired using an objective of focal length 1.25 cm and an eyepiece of focal length 5 cm. How will you set up the compound microscope?
Draw a ray diagram showing image formation in a compound microscope ?
Draw a ray diagram showing the image formation by a compound microscope. Hence obtained expression for total magnification when the image is formed at infinity.
Draw a ray diagram to show the working of a compound microscope. Deduce an expression for the total magnification when the final image is formed at the near point.
In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. If the eye piece has a focal length of 5 cm and the final image is formed at the near point, estimate the magnifying power of the microscope.
A simple microscope is rated 5 X for a normal relaxed eye. What will be its magnifying power for a relaxed farsighted eye whose near point is 40 cm?
Draw a labelled ray diagram showing the formation of image by a compound microscope in normal adjustment. Derive the expression for its magnifying power.
| A compound microscope consists of two converging lenses. One of them, of smaller aperture and smaller focal length, is called objective and the other of slightly larger aperture and slightly larger focal length is called eye-piece. Both lenses are fitted in a tube with an arrangement to vary the distance between them. A tiny object is placed in front of the objective at a distance slightly greater than its focal length. The objective produces the image of the object which acts as an object for the eye-piece. The eye-piece, in turn, produces the final magnified image. |
The focal lengths of the objective and eye-piece of a compound microscope are 1.2 cm and 3.0 cm respectively. The object is placed at a distance of 1.25 cm from the objective. If the final image is formed at infinity, the magnifying power of the microscope would be:
