Expand the Following: (3x + 4) (2x - 1) - Mathematics

Expand the following:
(3x + 4) (2x - 1)

बेरीज

(3x + 4) (2x - 1)
= 6x²- 3x + 8x - 4
= 6x² + 5x - 4
(Using identity : (x+ a) (x -b)
= x² + (a - b) x - ab).

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पाठ 4: Expansions - Exercise 4.1

पाठ 4 Expansions
Exercise 4.1 | Q 1.4

if `x^2 + 1/x^2 = 79` Find the value of `x + 1/x`

Simplify the following products:

`(2x^4 - 4x^2 + 1)(2x^4 - 4x^2 - 1)`

Write in the expanded form:

`(m + 2n - 5p)^2`

Find the cube of the following binomials expression :

\[2x + \frac{3}{x}\]

If \[x - \frac{1}{x} = \frac{15}{4}\], then \[x + \frac{1}{x}\] =

Find the square of : 3a + 7b

Evalute : `( 7/8x + 4/5y)^2`

If a + `1/a`= 6 and a ≠ 0 find :
(i) `a - 1/a (ii) a^2 - 1/a^2`

Use the direct method to evaluate :
(2+a) (2−a)

Expand the following:
(x - 5) (x - 4)