Advertisements
Advertisements
प्रश्न
Expand.
(101)3
बेरीज
Advertisements
उत्तर
(101)3
= `(100 + 1)^3`
= `(100)^3 + (1)^3 + 3 xx (100)^2 xx 1 + 3 xx 100 xx (1)^2`
= 1000000 + 1 + 30000 + 300
= 1030301
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Find the cube of : 5a + 3b
Two positive numbers x and y are such that x > y. If the difference of these numbers is 5 and their product is 24, find:
- Sum of these numbers
- Difference of their cubes
- Sum of their cubes.
Expand : (3x + 5y + 2z) (3x - 5y + 2z)
Expand : (3x - 5y - 2z) (3x - 5y + 2z)
If X ≠ 0 and X + `1/"X"` = 2 ; then show that :
`x^2 + 1/x^2 = x^3 + 1/x^3 = x^4 + 1/x^4`
Find the cube of: `4"p" - (1)/"p"`
If `5x + (1)/(5x) = 7`; find the value of `125x^3 + (1)/(125x^3)`.
If `"m"^2 + (1)/"m"^2 = 51`; find the value of `"m"^3 - (1)/"m"^3`
If `"a" + 1/"a"` = 6, then find the value of `"a"^3 + 1/"a"^3`
(p + q)(p2 – pq + q2) is equal to _____________
