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प्रश्न
Evaluate without using a trigonometric table:
`sin 48° sec 42° + (sec 50°)/ ("cosec" 40°)`
बेरीज
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उत्तर
Given:
sin 48° ⋅ sec 42° + `(sec 50°)/("cosec" 40°)`
Step 1:
sec 42° = `1/(cos 42°)`
cos 42° = sin 48°
sin 48° ⋅ sec 42° = `(sin 48°)/(cos42°) = (sin48°)/(sin 48°) = 1`
Step 2:
cosec 40° = `1/(sin 40°) = 1/(cos 50°)`
`(sec 50°)/("cosec" 40°) = (1/(cos 50°))/(1/(cos 50°)) = 1`
1 + 1 = 2
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