मराठी

Evaluate without using a trigonometric table: 2⁢tan⁡36°cot⁡54° +3⁢cot⁡38°tan⁡52° −2⁢sec⁡41°cosec49° - Mathematics

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प्रश्न

Evaluate without using a trigonometric table:

`(2 tan 36°)/(cot 54°) + (3 cot 38°)/(tan 52°) − (2 sec 41°)/("cosec" 49°)` 

बेरीज
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उत्तर

Use co-function identities:

`cot(90° −  θ) = tan θ, tan(90° −  θ) = cot θ, "cosec"(90° −  θ) = sec θ.`

`(2 tan 36°)/(cot 54°) = (2 tan 36°)/(tan 36°) = 2`

`(3 cot 38°)/(tan 52°) = (3 cot 38°)/(cot 38°) = 3`

`(2 sec 41°)/("cosec"  49°) = (2 sec 41°)/(sec 41°) = 2`

2 + 3 − 2   ...[Adding]

= 3

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पाठ 19: Trigonometry - EXERCISE 19B [पृष्ठ २३३]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 19 Trigonometry
EXERCISE 19B | Q II. 7. | पृष्ठ २३३
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