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प्रश्न
Evaluate without using a trigonometric table:
`(2 tan 36°)/(cot 54°) + (3 cot 38°)/(tan 52°) − (2 sec 41°)/("cosec" 49°)`
बेरीज
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उत्तर
Use co-function identities:
`cot(90° − θ) = tan θ, tan(90° − θ) = cot θ, "cosec"(90° − θ) = sec θ.`
`(2 tan 36°)/(cot 54°) = (2 tan 36°)/(tan 36°) = 2`
`(3 cot 38°)/(tan 52°) = (3 cot 38°)/(cot 38°) = 3`
`(2 sec 41°)/("cosec" 49°) = (2 sec 41°)/(sec 41°) = 2`
2 + 3 − 2 ...[Adding]
= 3
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