Advertisements
Advertisements
प्रश्न
Evaluate the following: `(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`
Advertisements
उत्तर
`(3sin37°)/(cos53°) - (5"cosec"39°)/(sec51°) + (4tan23° tan37° tan67° tan53°)/(cos17° cos67° "cosec"73° "cosec"23°)`
= `(3sin(90° - 53°))/(cos53°) - (5"cosec"(90° - 51°))/(sec51°) + (4tan(90° - 67°) tan(90° - 53°) xx 1/(cot67°) xx 1/(cot53°))/(cos(90° - 73°) cos(90° - 23°) xx 1/(sin73°) xx 1/(sin23°)`
= `(3cos53°)/(cos53°) - (5sec51°)/(sec51°) + (4 cos67° cos53° xx 1/(cot67°) xx 1/cot53°)/(sin73° sin23° xx 1/(sin73°) xx 1/sin23°)`
= 3 - 5 + 4
= 2.
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if 2 sin 3 A = 1
Solve the following equation for A, if 2 sin A = 1
Solve for 'θ': `sec(θ/2 + 10°) = (2)/sqrt(3)`
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
In the given figure, ∠B = 60°, ∠C = 30°, AB = 8 cm and BC = 24 cm. Find:
a. BE
b. AC
Find the value 'x', if:
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°
If cosθ = sin60° and θ is an acute angle find the value of 1- 2 sin2θ
Prove the following: `(tan(90° - θ)cotθ)/("cosec"^2 θ)` = cos2θ
