मराठी

Evaluate the Following Determinant: ∣ ∣ ∣ Cos θ − Sin θ Sin θ Cos θ ∣ ∣ ∣

Advertisements
Advertisements

प्रश्न

Evaluate the following determinant:

\[\begin{vmatrix}\cos \theta & - \sin \theta \\ \sin \theta & \cos \theta\end{vmatrix}\]

Advertisements

उत्तर

\[∆ = \cos^2 \theta - \left( - \sin^2 \theta \right)\]
\[ = \cos^2 \theta + \sin^2 \theta = 1\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Determinants - Exercise 6.1 [पृष्ठ १०]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 5 Determinants
Exercise 6.1 | Q 2.2 | पृष्ठ १०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×