Advertisements
Advertisements
प्रश्न
Evaluate: (a + 1)(a2 - a + 1) and (a - 1)(a2 + a + 1)
Advertisements
उत्तर
(a + 1)(a2 - a + 1) and (a - 1)(a2 + a + 1)
= a (a2 - a + 1) + 1 (a2 - a + 1)
= a3 - a2 + a + a2 - a + 1
= a3 + 1
(a - 1)(a2 + a + 1)
= a(a2 + a + 1) - 1(a2 + a + 1)
= a3 + a2 + a - a2 - a - 1
= a3 - 1
Now, (a + 1)(a2 - a + 1) + (a - 1)(a2 + a + 1)
= a3 + 1 + a3 - 1
= 2a3
APPEARS IN
संबंधित प्रश्न
Subtract: 4x from 8 - x
What must be subtracted from a2 + b2 + lab to get – 4ab + 2b2?
The perimeter of a triangle is 14a2 + 20a + 13. Two of its sides are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
If m = 9x2 - 4xy + 5y2 and n = - 3x2 + 2xy - y2 find: m - 3n
Multiply: 5x + 2y and 3xy
Copy and complete the following multi-plication:
3xy - 2x2 - 6x
× -5x2y
Multiply: x2 + 5yx - 3y2 and 2x2y
Simplify: `"3y"/4 -"y"/5`
Simplify: `"3y"/5 - "y + 2"/2`
Simplify: `7/30 "of" ("p"/3 + "7p"/15)`
