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Evaluate: π∫0π4cot2x.dx - Mathematics and Statistics

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प्रश्न

Evaluate: `int_0^(π/4) cot^2x.dx`

बेरीज
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उत्तर

`int_0^(π/4) cot^2x.dx`

= `int_0^(π/4) ("cosec"^2x - 1).dx`

= `int_0^(π/4) "cosec"^2x.dx - int_0^(π/4)1.dx`

= `[-cot x]_0^(π/4) - [x]_0^(π/4)`

= `[(-cot π/4) - (-cot 0)] - [π/4 - 0]`

= `-1 + cot 0 - pi/4`

The integral does not exist since cot 0 is not defined.

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Methods of Evaluation and Properties of Definite Integral
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Definite Integration - Exercise 4.2 [पृष्ठ १७१]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 4 Definite Integration
Exercise 4.2 | Q 1.03 | पृष्ठ १७१

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