Question

Draw the structure of the following compound.

Hex-2-en-4-ynoic acid

Answer 1

\[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - C ≡ C - CH = CH - C - OH}
\end{array}\]

Answer 2

\[\ce{\overset{6}{C}H3 - \overset{5}{C} ≡ \overset{4}{C} - \overset{3}{C}H = \overset{2}{C}H - \overset{1}{C}OOH}\]