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प्रश्न
Draw the chain isomers of hexane (C6H14).
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उत्तर १

उत्तर २
\[\ce{\underset{n-hexane}{H3C - H2C - H2C - H2C - H2C - CH3}}\]
\[\begin{array}{cc}
\ce{H3C - HC - H2C - H2C - CH3}\\
|\phantom{................}\\
\ce{\underset{iso-hexane}{H3C}\phantom{..............}}\\
\end{array}\]
\[\begin{array}{cc}
\ce{H3C}\phantom{.....}\\
|\phantom{.......}\\
\ce{H3C - C - H2C - CH3}\\
|\phantom{.......}\\
\ce{H3C}\phantom{.....}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{X ->[Br2/CCl4] CH2Br}\\
\phantom{......}|\\
\phantom{...........}\ce{CH2Br}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\end{array}\]
