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प्रश्न
Draw position isomers of butene (C4H8).
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उत्तर
\[\ce{\underset{But-1-ene}{H2C = HC - H2C - CH3}}\]
\[\ce{\underset{But-2-ene}{H3C - HC = CH - CH3}}\]
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\[\begin{array}{cc}
\phantom{.}\ce{H\phantom{...}H\phantom{...}O}\phantom{..}\\
\phantom{.}|\phantom{....}|\phantom{....}||\phantom{..}\\
\ce{H - C - C - C - OH}\\
\phantom{}|\phantom{....}|\phantom{......}\\
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\end{array}\]
