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प्रश्न
Divide 6x3y2z2 by 3x2yz.
बेरीज
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उत्तर
\[\frac{6 x^3 y^2 z^2}{3 x^2 yz} = \frac{6 \times x \times x \times x \times y \times y \times z \times z}{3 \times x \times x \times y \times z} = 2 x^{(3 - 2)} y^{(2 - 1)} z^{(2 - 1)} = 2xyz\]
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