Advertisements
Advertisements
प्रश्न
Divide:
acx2 + (bc + ad)x + bd by (ax + b)
Advertisements
उत्तर
\[\frac{ac x^2 + (bc + ad)x + bd}{(ax + b)}\]
\[ = \frac{ac x^2 + bcx + adx + bd}{(ax + b)}\]
\[ = \frac{cx(ax + b) + d(ax + b)}{(ax + b)}\]
\[ = \frac{(ax + b)(cx + d)}{(ax + b)}\]
\[ = cx + d\]
APPEARS IN
संबंधित प्रश्न
Write the degree of each of the following polynomials.
Divide 72xyz2 by −9xz.
Divide 14x2 − 53x + 45 by 7x − 9.
Divide x4 − 2x3 + 2x2 + x + 4 by x2 + x + 1.
Divide 6x3 − x2 − 10x − 3 by 2x − 3 and find the quotient and remainder.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 15z3 − 20z2 + 13z − 12 | 3z − 6 |
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 4y3 + 8y + 8y2 + 7 | 2y2 − y + 1 |
Using division of polynomials, state whether
z2 + 3 is a factor of z5 − 9z
Using division of polynomials, state whether
2x2 − x + 3 is a factor of 6x5 − x4 + 4x3 − 5x2 − x − 15
Divide: 8x − 10y + 6c by 2
