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प्रश्न
Divide:
acx2 + (bc + ad)x + bd by (ax + b)
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उत्तर
\[\frac{ac x^2 + (bc + ad)x + bd}{(ax + b)}\]
\[ = \frac{ac x^2 + bcx + adx + bd}{(ax + b)}\]
\[ = \frac{cx(ax + b) + d(ax + b)}{(ax + b)}\]
\[ = \frac{(ax + b)(cx + d)}{(ax + b)}\]
\[ = cx + d\]
संबंधित प्रश्न
Write each of the following polynomials in the standard form. Also, write their degree.
Divide x + 2x2 + 3x4 − x5 by 2x.
Divide 5x3 − 15x2 + 25x by 5x.
Divide 4z3 + 6z2 − z by −\[\frac{1}{2}\]
Divide 4y2 + 3y +\[\frac{1}{2}\] by 2y + 1.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 15y4 − 16y3 + 9y2 −\[\frac{10}{3}\] y+6 | 3y − 2 |
Divide the first polynomial by the second in each of the following. Also, write the quotient and remainder:
3x2 + 4x + 5, x − 2
Find whether the first polynomial is a factor of the second.
x + 1, 2x2 + 5x + 4
Divide:
ax2 − ay2 by ax + ay
7ab3 ÷ 14ab = 2b2
