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प्रश्न
Divide:
acx2 + (bc + ad)x + bd by (ax + b)
बेरीज
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उत्तर
\[\frac{ac x^2 + (bc + ad)x + bd}{(ax + b)}\]
\[ = \frac{ac x^2 + bcx + adx + bd}{(ax + b)}\]
\[ = \frac{cx(ax + b) + d(ax + b)}{(ax + b)}\]
\[ = \frac{(ax + b)(cx + d)}{(ax + b)}\]
\[ = cx + d\]
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