Advertisements
Advertisements
प्रश्न
Divide 27y3 by 3y
Advertisements
उत्तर
`(27y^3)/(3y) = 27/3 y^(3 - 1)`
= 9y2
APPEARS IN
संबंधित प्रश्न
Divide the given polynomial by the given monomial.
(3y8 − 4y6 + 5y4) ÷ y4
Write each of the following polynomials in the standard form. Also, write their degree.
Divide −4a3 + 4a2 + a by 2a.
Divide\[\sqrt{3} a^4 + 2\sqrt{3} a^3 + 3 a^2 - 6a\ \text{by}\ 3a\]
Divide 9x2y − 6xy + 12xy2 by −\[\frac{3}{2}\]
Divide x4 + x2 + 1 by x2 + x + 1.
Divide 9x4 − 4x2 + 4 by 3x2 − 4x + 2 and find the quotient and remainder.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 6y5 − 28y3 + 3y2 + 30y − 9 | 2y2 − 6 |
Statement A: If 24p2q is divided by 3pq, then the quotient is 8p.
Statement B: Simplification of `((5x + 5))/5` is 5x
The denominator of a fraction exceeds Its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, we get `3/2`. Find the original fraction.
