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Displacement versus time curve for a particle executing S.H.M. is shown in figure. Identify the points marked at which (i) velocity of the oscillator is zero, (ii) speed of the oscillator is maximum.

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प्रश्न

Displacement versus time curve for a particle executing S.H.M. is shown in figure. Identify the points marked at which (i) velocity of the oscillator is zero, (ii) speed of the oscillator is maximum.

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उत्तर

In SHM y-t graph, zero displacement values correspond to the mean position; where the velocity of the oscillator is maximum.

Whereas the crest and troughs represent extreme positions, where displacement is maximum and velocity of the oscillator is minimum and is zero. Hence,

  1. A, C, E and G are either crests or trough having zero velocity.
  2. Speed is maximum at mean positions represented by B, D, F, and H paints.
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Energy in Simple Harmonic Motion
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Oscillations - Exercises [पृष्ठ १०२]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
पाठ 14 Oscillations
Exercises | Q 14.19 | पृष्ठ १०२

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