मराठी

Differentiate Tan − 1 ( 4 X 1 − 4 X 2 ) , − 1 2 < X < 1 2 ? - Mathematics

Advertisements
Advertisements

प्रश्न

Differentiate \[\tan^{- 1} \left( \frac{4x}{1 - 4 x^2} \right), - \frac{1}{2} < x < \frac{1}{2}\] ?

बेरीज
Advertisements

उत्तर

\[\text{ Let, y } = \tan^{- 1} \left\{ \frac{4x}{1 - 4 x^2} \right\}\]

\[\text{ put 2x } = \tan\theta\]

\[ \Rightarrow y = \tan^{- 1} \left\{ \frac{2 \tan\theta}{1 - \tan^2 \theta} \right\}\]

\[ \Rightarrow y = \tan^{- 1} \left( \tan2\theta \right) . . . \left( i \right)\]

\[\text{ Here }, - \frac{1}{2} < x < \frac{1}{2}\]

\[ \Rightarrow - 1 < 2x < 1\]

\[ \Rightarrow - 1 < \tan\theta < 1\]

\[ \Rightarrow - \frac{\pi}{4} < \theta < \frac{\pi}{4}\]

\[ \Rightarrow - \frac{\pi}{2} < 2\theta < \frac{\pi}{2}\]

\[\text{ So, from equation } \left( i \right), \]

\[ y = 2\theta ............\left[ \text{ Since }, \tan^{- 1} \left( \tan\theta \right) = \theta, \text{ if }\theta \in \left( - \frac{\pi}{2}, \frac{\pi}{2} \right) \right]\]

\[ \Rightarrow y = 2 \tan^{- 1} \left( 2x \right) ...........\left[ \text{ Since }, 2x = \tan\theta \right]\]

\[\text{ Differentiating it with respect to x }, \]

\[\frac{d y}{d x} = 2\left( \frac{1}{1 + \left( 2x \right)^2} \right)\frac{d}{dx}\left( 2x \right)\]

\[ \Rightarrow \frac{d y}{d x} = 2\left( \frac{1}{1 + 4 x^2} \right) \times 2\]

\[ \therefore \frac{d y}{d x} = \frac{4}{1 + 4 x^2}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Differentiation - Exercise 11.03 [पृष्ठ ६३]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 11 Differentiation
Exercise 11.03 | Q 16 | पृष्ठ ६३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Prove that `y=(4sintheta)/(2+costheta)-theta `


​Differentiate the following function from first principles \[e^\sqrt{\cot x}\] .


Differentiate `2^(x^3)` ?


Differentiate \[3^{x \log x}\] ?


Differentiate \[\log \left( x + \sqrt{x^2 + 1} \right)\] ?


Differentiate \[\frac{3 x^2 \sin x}{\sqrt{7 - x^2}}\] ?


Differentiate \[\left( \sin^{- 1} x^4 \right)^4\] ?


If  \[y = \left( x - 1 \right) \log \left( x - 1 \right) - \left( x + 1 \right) \log \left( x + 1 \right)\] , prove that \[\frac{dy}{dc} = \log \left( \frac{x - 1}{1 + x} \right)\] ?


If \[y = \sqrt{a^2 - x^2}\] prove that  \[y\frac{dy}{dx} + x = 0\] ?


Differentiate \[\sin^{- 1} \left( \frac{1}{\sqrt{1 + x^2}} \right)\] with respect to x.


If \[y = \sin^{- 1} \left( 6x\sqrt{1 - 9 x^2} \right), - \frac{1}{3\sqrt{2}} < x < \frac{1}{3\sqrt{2}}\] \[\frac{dy}{dx} \] ?


Differentiate \[{10}^{ \log \sin x }\] ?


Find  \[\frac{dy}{dx}\]  \[y = \frac{e^{ax} \cdot \sec x \cdot \log x}{\sqrt{1 - 2x}}\] ?

 


If \[x^{16} y^9 = \left( x^2 + y \right)^{17}\] ,prove that \[x\frac{dy}{dx} = 2 y\] ?


If \[y = \sin \left( x^x \right)\] prove that  \[\frac{dy}{dx} = \cos \left( x^x \right) \cdot x^x \left( 1 + \log x \right)\] ?


If \[e^y = y^x ,\] prove that\[\frac{dy}{dx} = \frac{\left( \log y \right)^2}{\log y - 1}\] ?


If  \[y = \sqrt{\tan x + \sqrt{\tan x + \sqrt{\tan x + . . to \infty}}}\] , prove that \[\frac{dy}{dx} = \frac{\sec^2 x}{2 y - 1}\] ?

 


If \[y = \left( \tan x \right)^{\left( \tan x \right)^{\left( \tan x \right)^{. . . \infty}}}\], prove that \[\frac{dy}{dx} = 2\ at\ x = \frac{\pi}{4}\] ?

 


If \[y = e^{x^{e^x}} + x^{e^{e^x}} + e^{x^{x^e}}\], prove that  \[\frac{dy}{dx} = e^{x^{e^x}} \cdot x^{e^x} \left\{ \frac{e^x}{x} + e^x \cdot \log x \right\}+ x^{e^{e^x}} \cdot e^{e^x} \left\{ \frac{1}{x} + e^x \cdot \log x \right\} + e^{x^{x^e}} x^{x^e} \cdot x^{e - 1} \left\{ x + e \log x \right\}\]

 


Find \[\frac{dy}{dx}\] ,When \[x = a \left( 1 - \cos \theta \right) \text{ and } y = a \left( \theta + \sin \theta \right) \text{ at } \theta  = \frac{\pi}{2}\] ?


Find \[\frac{dy}{dx}\] ,When \[x = e^\theta \left( \theta + \frac{1}{\theta} \right) \text{ and } y = e^{- \theta} \left( \theta - \frac{1}{\theta} \right)\] ?


Differentiate  \[\sin^{- 1} \sqrt{1 - x^2}\] with respect to \[\cos^{- 1} x, \text { if}\]\[x \in \left( 0, 1 \right)\]  ?

 


Differentiate \[\sin^{- 1} \left( 4x \sqrt{1 - 4 x^2} \right)\] with respect to \[\sqrt{1 - 4 x^2}\] , if \[x \in \left( - \frac{1}{2 \sqrt{2}}, \frac{1}{\sqrt{2 \sqrt{2}}} \right)\] ?

Differentiate \[\sin^{- 1} \left( 2x \sqrt{1 - x^2} \right)\] with respect to  \[\sec^{- 1} \left( \frac{1}{\sqrt{1 - x^2}} \right)\], if \[x \in \left( 0, \frac{1}{\sqrt{2}} \right)\] ?


If \[y = \sec^{- 1} \left( \frac{x + 1}{x - 1} \right) + \sin^{- 1} \left( \frac{x - 1}{x + 1} \right)\] then write the value of \[\frac{dy}{dx} \] ?


If \[f\left( x \right) = \sqrt{x^2 - 10x + 25}\]  then the derivative of f (x) in the interval [0, 7] is ____________ .


If \[f\left( x \right) = \left| x - 3 \right| \text { and }g\left( x \right) = fof \left( x \right)\]  is equal to __________ .


Find the second order derivatives of the following function tan−1 x ?


If y = cot x show that \[\frac{d^2 y}{d x^2} + 2y\frac{dy}{dx} = 0\] ?


If y = 500 e7x + 600 e−7x, show that \[\frac{d^2 y}{d x^2} = 49y\] ?


\[\text{ If x } = a\left( \cos t + \log \tan\frac{t}{2} \right) \text { and y } = a\left( \sin t \right), \text { evaluate } \frac{d^2 y}{d x^2} \text { at t } = \frac{\pi}{3} \] ?


\[\text { If x } = a\left( \cos2t + 2t \sin2t \right)\text {  and y } = a\left( \sin2t - 2t \cos2t \right), \text { then find } \frac{d^2 y}{d x^2} \] ?


If \[y = 1 - x + \frac{x^2}{2!} - \frac{x^3}{3!} + \frac{x^4}{4!}\] .....to ∞, then write  \[\frac{d^2 y}{d x^2}\] in terms of y ?


If x = f(t) and y = g(t), then write the value of \[\frac{d^2 y}{d x^2}\] ?


If y = axn+1 + bx−n, then \[x^2 \frac{d^2 y}{d x^2} =\] 

 


If y = a sin mx + b cos mx, then \[\frac{d^2 y}{d x^2}\]   is equal to

 


If x = f(t) and y = g(t), then \[\frac{d^2 y}{d x^2}\] is equal to

 


If x = sin t and y = sin pt, prove that \[\left( 1 - x^2 \right)\frac{d^2 y}{d x^2} - x\frac{dy}{dx} + p^2 y = 0\] .


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×