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Differentiate ( Sin − 1 X 4 ) 4 ? - Mathematics

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प्रश्न

Differentiate \[\left( \sin^{- 1} x^4 \right)^4\] ?

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उत्तर

\[\text{Let }y = \left( \sin^{- 1} x^4 \right)^4\]

Differentiate it with respect to x we get,

\[\frac{d y}{d x} = \frac{d}{dx} \left( \sin^{- 1} x^4 \right)^4 \]

\[ = 4 \left( \sin^{- 1} x^4 \right)^3 \frac{d}{dx}\left( \sin^{- 1} x^4 \right) \left[ \text{ Using chain rule} \right]\]

\[ = 4 \left( \sin^{- 1} x^4 \right)^3 \frac{1}{\sqrt{1 - \left( x^4 \right)^2}}\frac{d}{dx}\left( x^4 \right) \left[ \text{Using chain rule} \right]\]

\[ = 4 \left( \sin^{- 1} x^4 \right)^3 \frac{4 x^3}{\sqrt{1 - x^8}}\]

\[ = \frac{16 x^3 \left( \sin^{- 1} x^4 \right)^3}{\sqrt{1 - x^8}}\]

\[So, \frac{d}{dx} \left( \sin^{- 1} x^4 \right)^4 = \frac{16 x^3 \left( \sin^{- 1} x^4 \right)^3}{\sqrt{1 - x^8}}\]

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पाठ 11: Differentiation - Exercise 11.02 [पृष्ठ ३७]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 11 Differentiation
Exercise 11.02 | Q 47 | पृष्ठ ३७

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