Advertisements
Advertisements
प्रश्न
Differentiate between the 'distance of the closest approach' and the 'impact parameter.'
Advertisements
उत्तर
The phrase "distance of closest approach" refers to the lowest separation required between two particles or objects during the interaction, for as when they collide. Due to the fact that this is where the particles are closest to one another, it is frequently expressed in terms of physical distance, such as metres or centimetres. The closest approach distance depends on the initial conditions of the contact, including the initial positions, velocities, and forces of the particles.
The "impact parameter," on the other hand, measures how far a particle's trajectory is from a target object during a collision, such as a nucleus. This word refers to the angle between the particle's initial trajectory and the centre of the target object. In order to better comprehend the dynamics of the collision, the impact parameter is sometimes stated in terms of physical distance, such as metres or millimetres.
APPEARS IN
संबंधित प्रश्न
With the help of a neat labelled diagram, describe the Geiger- Marsden experiment
In the ground state of ______ electrons are in stable equilibrium, while in ______ electrons always experience a net force.
Write two important limitations of Rutherford's nuclear model of the atom.
If the radius of second electron orbit in hydrogen atom be r then the radius of the third orbit will be ______.
An automobile moves on a road with a speed of 54 km h−1. The radius of its wheels is 0.45 m and the moment of inertia of the wheel about its axis of rotation is 3 kg m2. If the vehicle is brought to rest in l 5s, the magnitude of average torque transmitted by its brakes to the wheel is:
Plutonium decays with half of 24000 years. If plutonium is store for 72000 yrs. The fraction of .its that remain:-
The radius of electron's second stationary orbit in Bohr's atom is R. The radius of 3rd orbit will be:-
The ratio active Nude 7N13 decays 6C13 through the emission of
Would the Bohr formula for the H-atom remain unchanged if proton had a charge (+4/3)e and electron a charge (−3/4)e, where e = 1.6 × 10–19C. Give reasons for your answer.
An alpha nucleus of energy `1/2`mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to ______.
- v2
- `1/"m"`
- `1/"v"^2`
- `1/"Ze"`
