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प्रश्न
Describe the reaction that show
Concentrated sulphuric acid behaves as oxidizing agent.
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उत्तर
Concentrated sulphuric acid is an oxidizing agent as sulphuric acid decomposes to form nascent oxygen which helps in the oxidation of sulphur and carbon.
H2SO4 → H2O + SO2 + [O]
C + 2[O] → CO2
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संबंधित प्रश्न
Write balanced chemical equations to show : The oxidizing action of conc. Sulphuric acid on carbon
In the contact process for the manufacture of sulphuric acid give the equations for the conversion of sulphur trioxide to sulphuric acid.
State the conditions required for the given reaction to take place:
Any two conditions for the conversion of sulphur dioxide to sulphur trioxide
What would you observe in the following case?
Hot concentrated sulphuric acid is added to sodium chloride crystals.
- Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
- In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
- What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
- Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
Write balanced equation for potassium hydrogen carbonate and dilute sulphuric acid.
Dilute sulphuric acid will produce a white precipitate when added to a solution of ______.
State your observation of the following case:
When dilute hydrochloric acid is added to sodium carbonate crystals.
Give a chemical test to distinguish between dilute sulphuric acid and dilute hydrochloric acid (using lead nitrate solution).
Write a balanced equation for the following conversion:
Lead sulphate from lead nitrate and sulphuric acid.
