Advertisements
Advertisements
प्रश्न
Describe Hinsberg method for the identification of primary, secondary and tertiary amines. Also write the chemical equations of the reactions involved.
Advertisements
उत्तर
Hinsberg's method: Benzenesulphonyl chloride (C6H5SO2Cl) (known as Hinsberg’s reagent) reacts with primary and secondary amines to form sulphonamides. The method is used for the distinction of primary, secondary and tertiary amines.
Sulphonamide formed in case of a primary (1°) amine is soluble in an alkali.
Sulphonamide formed in case of a secondary (2°) amine remains insoluble in an alkali.
A tertiary (3°) amine does not give a positive Hinsberg test.
APPEARS IN
संबंधित प्रश्न
Distinguish between the following pairs of compounds: Aniline and N-methylaniline
Give a plausible explanation for the following:
Why do primary amines have higher boiling points than tertiary amines?
When primary amine reacts with CHCl3 in alcoholic KOH, the product is _______.
(A) aldehyde
(B) alcohol
(C) cyanide
(D) an isocyanide
What is the action of Benzene Sulphonyl Chloride on primary, secondary and tertiary
amines?
Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.
Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.
Arrange the following in the increasing order of their boiling points:
A: Butanamine
B: N, N-Dimethylethanamine
C: N- Etthylethanaminamine
Give reasons:
(CH3)2NH is more basic than (CH3)3N in an aqueous solution.
In the reaction \[\ce{C6H5NH2 + CHCl3 + 3KOH -> A + 3B + 3C}\] the product A is:
Among dimethylamine (pKb = 3.27) and diethylamine (pKb = 3.0), which one is more basic?
