Advertisements
Advertisements
प्रश्न
Construct a quadrilateral PQRS, in which ∠Q = 45°, ∠R = 90°, QR = 5 cm, PQ = 9 cm and Rs = 7 cm.
Advertisements
उत्तर
Steps of construction:
Step I: Draw QR = 5 cm .
Step II: Construct ∠PQR = 45° at Q .
Step III : With Q as the centre and radius 9 cm, cut off QP = 9 cm .
Step IV: Construct ∠QRS = 90° at R .
Step V : With R as the centre and radius 7 cm, cut off RS = 7 cm .
Since, the line segment PQ and RS intersect each other, the quadrilateral cannot be constructed .

संबंधित प्रश्न
Construct the following quadrilaterals.
Quadrilateral PLAN
PL = 4 cm
LA = 6.5 cm
∠P = 90°
∠A = 110°
∠N = 85°
Construct the following quadrilaterals.
Parallelogram HEAR
HE = 5 cm
EA = 6 cm
∠R = 85°
Construct the following quadrilaterals.
Rectangle OKAY
OK = 7 cm
KA = 5 cm
Construct, if possible, a quadrilateral ABCD in which AB = 6 cm, BC = 7 cm, CD = 3 cm, AD = 5.5 cm and AC = 11 cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD < AC).
Construct a quadrilateral ABCD in which AB = BC = 6 cm, AD = DC = 4.5 cm and ∠B = 120°.
Construct a quadrilateral ABCD given BC = 6.6 cm, CD = 4.4 cm, AD = 5.6 cm and ∠D = 100° and ∠C= 95°.
Construct a quadrilateral PQRS, where PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°.
In a parallelogram PQRS, if ∠P = 60°, then other three angles are ______.
To construct a unique parallelogram, the minimum number of measurements required is ______.
Is it possible to construct a quadrilateral ROAM in which RO = 4 cm, OA = 5 cm, ∠O = 120°, ∠R = 105° and ∠A = 135°? If not, why?
