Question

Construct a triangle with sides 5 cm, 6 cm and 7 cm and then construct another triangle whose sides are `3/4` times the corresponding sides of the first triangle.

Answer 1

Steps of construction:

1. Draw a line segment BC = 5 cm.
2. With B and C as centres and radii 7 cm and 6 cm draw two arcs, which intersects at A.
3. Join BA and CA to obtain ΔABC.
4. Below BC, make an acute angle CBX.
5. Mark B₁, B₂, B₃, B₄ on BX such that BB₁ = B₁B₂ = B₂B₃ = B₃B₄·
6. Join B₄ to C.
7. Draw a line segment B₃C || B₄C to meet BC at C.
8. Draw line segment C'A' || CA to meet AB at A'. Hence, A'BC' is the required triangle.