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प्रश्न
Construct a quadrilateral ABCD, when AB = 5.2 cm, BC = 4.5, CD = 4 cm, AD = 5 cm and ∠A = 75°
भौमितिक रेखाचित्रे
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उत्तर
Given:
- AB = 5.2 cm
- BC = 4.5 cm
- CD = 4 cm
- AD = 5 cm
- ∠A = 75°

Steps of construction:
- Draw a line segment AB = 5.2 cm.
- At point A, construct an angle of 75°.
- From point A along the ray forming the 75° angle, cut off a length AD = 5 cm and mark point D.
- Join B and C such that BC = 4.5 cm.
- With center B and radius = 4.5 cm, draw an arc to mark the possible location of C.
- With center D and radius = 4 cm, draw an arc to intersect the previous arc and mark that point as C.
- Join BC and CD to complete the quadrilateral ABCD.
The quadrilateral ABCD, with sides AB = 5.2 cm, BC = 4.5 cm, CD = 4 cm, AD = 5 cm and angle ∠A = 75° is constructed by drawing AB first, then constructing angle 75° at A, marking D and locating C as intersection of arcs from B and D with radius BC and CD respectively, then joining all vertices.
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पाठ 12: Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons) - EXERCISE 12B [पृष्ठ १४९]
