मराठी

Connect a 1.5 V dry cell to a resistor (low resistance), an ammeter and a key in series as shown in Fig. Record the electric current shown by the ammeter. Replace the single cell by 2, 3, … cells.

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प्रश्न

Connect a 1.5 V dry cell to a resistor (low resistance), an ammeter and a key in series as shown in Fig. Record the electric current shown by the ammeter. Replace the single cell by 2, 3, … cells. For the number of cells, record the electric current as is done for you in the table given below: 

S.No. P.d. (V)
(in volts)
Electric current
(in amperes)
V / I
1. 1.5 3 ...
2. 3.0 6 ...
3. 4.5 9 ...
4. ... ... ...

The figure shows that increasing the number of cells increases the potential difference across a conductor, causing more electric current to flow. Similarly, water flow increases with greater height or pressure.

By connecting identical conductors of aluminium, iron, etc., in the gap. Record your observations for electric current and voltage in each case. Find the ratio \(\dfrac{V}{I}=R\) in each case. What do you observe?

कृती
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उत्तर

Aim

To study the relationship between potential difference (\(V\)) and electric current (\(I\)) for identical conductors made of different metals and determine their resistance.

Apparatus Required

Battery, ammeter, voltmeter, key, rheostat, connecting wires, and identical wires of aluminium, iron, copper and constantan.

Procedure

  1. Connect a battery, ammeter, key and conductor in series. Connect a voltmeter in parallel across the conductor.

  2. Close the key and record the potential difference (\(V\)) and current (\(I\)).

  3. Change the potential difference and record the corresponding current.

  4. Calculate the ratio \(\dfrac{V}{I}\) for each reading.

  5. Repeat the experiment using identical wires of aluminium, iron, copper and constantan.

  6. Keep the temperature constant throughout the experiment.

Observation Table

The following are illustrative values, not actual experimental readings. The wires are assumed to have equal length and cross-sectional area.

Conductor

Potential difference \(V\) (V)

Current \(I\) (A)

Resistance \(\dfrac{V}{I}\) (Ω)

Copper

\(2\)

\(4.0\)

\(0.5\)

Copper

\(4\)

\(8.0\)

\(0.5\)

Aluminium

\(2\)

\(2.5\)

\(0.8\)

Aluminium

\(4\)

\(5.0\)

\(0.8\)

Iron

\(2\)

\(0.8\)

\(2.5\)

Iron

\(4\)

\(1.6\)

\(2.5\)

Constantan

\(2\)

\(0.2\)

\(10\)

Constantan

\(4\)

\(0.4\)

\(10\)

Calculation

According to Ohm’s law,

\[ V=IR \]

Therefore,

\[{R=\frac{V}{I}} \]

For example, for copper:

\[ R=\frac{2}{4}=0.5\ \Omega \]

Observation

  1. The ratio \(\dfrac{V}{I}\) remains constant for a particular conductor at constant temperature.

  2. Different conductors have different resistances, even when their lengths and cross-sectional areas are equal.

  3. Copper offers the least resistance among the four materials, while constantan offers the greatest resistance.

  4. The \(V-I\) graph is a straight line passing through the origin for each conductor.

Result/Conclusion

The electric current flowing through a conductor is directly proportional to the potential difference across its ends, provided its temperature remains constant.

\[{V\propto I} \]
The ratio of potential difference to current is constant for a particular conductor and is called its resistance.

For identical conductors:

\[{R_{\text{copper}}<R_{\text{aluminium}}<R_{\text{iron}}<R_{\text{constantan}}} \]
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पाठ 4: Electricity and Magnetism - Activity 4.1 [पृष्ठ २२४]

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फ्रँक Physics Part 2 [English] Class 10 ICSE
पाठ 4 Electricity and Magnetism
Activity 4.1 | Q 2. | पृष्ठ २२४
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