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प्रश्न
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each illustrates the above-mentioned properties of sulphuric acid.
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उत्तर
- Oxidising agent: Concentrated sulphuric acid as an oxidising agent oxidises carbon to carbon dioxide.
\[\ce{\underset{Carbon}{C} + 2H2HO4 -> \underset{Carbon dioxide}{CO2} + 2SO2 + 2H2O}\] - Non-volatile acid: Concentrated sulphuric acid has a high boiling point (338°C) that is why it is said to be a non-volatile compound; therefore, it is used for preparing volatile acids like hydrochloric acids and nitric acids from their salts by double decomposition.
\[\ce{H2SO4 + NaCl -> NaHSO4 + HCl}\]
संबंधित प्रश्न
Write a balanced chemical equation for each of the following reactions :
Action of dilute sulphuric acid on sodium hydroxide.
Complete the following equations :
C + cons. H2SO4
How does sulphuric acid occur in nature?
Give reason for the following:
When diluting concentrated sulphuric acid, the acid should be added to water and not water to the acid.
Give examples of the use of sulphuric acid as
An electrolyte in everyday use
How will you identify?
Sulphur dioxide gas
Name the following:
A sulphate insoluble in water.
Sulphuric acid is manufactured by the contact process.
Name the chemical used to dissolve SO3 and also name the product formed. Give all the main reactions to this process.
Write a balanced chemical equation:
When hot and concentrated sulphuric acid reacts with the sugar.
What property of Sulphuric acid is exhibited in the following case?
In the preparation of HCI gas when it reacts with Sodium chloride.
