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प्रश्न
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each illustrates the above-mentioned properties of sulphuric acid.
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उत्तर
- Oxidising agent: Concentrated sulphuric acid as an oxidising agent oxidises carbon to carbon dioxide.
\[\ce{\underset{Carbon}{C} + 2H2HO4 -> \underset{Carbon dioxide}{CO2} + 2SO2 + 2H2O}\] - Non-volatile acid: Concentrated sulphuric acid has a high boiling point (338°C) that is why it is said to be a non-volatile compound; therefore, it is used for preparing volatile acids like hydrochloric acids and nitric acids from their salts by double decomposition.
\[\ce{H2SO4 + NaCl -> NaHSO4 + HCl}\]
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संबंधित प्रश्न
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Name the chemical used to dissolve SO3 and also name the product formed. Give all the main reactions to this process.
Which property of sulphuric acid accounts for its use as a dehydrating agent?
