Advertisements
Advertisements
प्रश्न
Concentrated nitric acid oxidizes phosphorous to phosphoric acid according to the following equation :
P + 5HNO3 → H3PO4 + H2O + 5NO2
What mass of nitric acid will be consumed at the same time?
Advertisements
उत्तर
Given equation is :
P + 5HNO3 → H3PO4 + H2O + 5NO2
Molecular mass of nitric acid = 63
31g of phosphorous will consume = 6 g of nitric acid.
APPEARS IN
संबंधित प्रश्न
Give balanced chemical equations for the following conversions A, B, and C:
Aluminium carbide reacts with water according to the following equation :
`Al_4C_3 + 12H_2O-> 4Al(OH)_3 + 3CH_4`
1)What mass of aluminium hydroxide is formed from 12g of aluminium carbide?
2) What volume of methane at s.t.p. is obtained from 12g of aluminium carbide?
[Relatively molecular weight of `Al_4Cl_3 = 144; Al(OH)_3 = 78]`
Calculate the percentage composition of oxygen in lead nitrate [Pb(NO3)2]. [Pb = 207, N= 14, O = 16]
Potassium nitrate on strong heating decomposes as under :
2KNO3 → 2KNO2 + O2
Calculate : Weight of potassium nitrite formed.
(K = 39, 0 = 16, N = 14)
The reaction of potassium permanganate (VII) with acidified iron (II) sulphate is given below:
2KMno4 + 10FeSO4 + 8H2O → K2SO4 + 2MnSO4 + 5Fe2(SO4)3 + 8H2O
If 15.8g of potassium permanganate (VII) was used in the reaction, calculate the mass of iron (II) sulphate used in the above reaction.
A compound 'X' consists of 4.8% of C and 95.2% of Br by mass.
If the vapour density of the compound is 252, what is the molecular formula of the compound?
4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.
- Write the equation for the reaction.
- What is the mass of 4.5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100).
- What is the volume of carbon dioxide liberated at STP?
- What mass of calcium chloride is formed? (Relative molecular mass of calcium chloride is 111).
- How many moles of HCl are used in this reaction?
Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C3H5).
(Atomic mass: C = 14, O = 16, H = 1, Molar Volume = 22.4 dm3 at STP.)
Correct the statement, if required.
Under similar conditions of temperature and pressure, two volumes of hydrogen combined with two volumes of oxygen will give two volumes of water vapour.
When heated, potassium permanganate decomposes according to the following equation :
\[\ce{2KMnO4 -> \underset{\text{solid residue}}{K2MnO4 + MnO2} + O2}\]
(a) Some potassium permanganate was heated in the test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.
(b) Given that the molecular mass of potassium permanganate is 158. What volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate? (Molar volume at room temperature is 24 litres)
