Question

Compute the following:

`[(cos^2x, sin^2x),(sin^2x, cos^2x)] + [(sin^2x, cos^2x), (cos^2x, sin^2x)]`

Answer 1

`[(cos^2x, sin^2x),(sin^2x, cos^2x)] + [(sin^2x, cos^2x), (cos^2x, sin^2x)]`

= `[(cos^2x + sin^2x, sin^2 + cos^2x), (sin^2x + cos^2x, cos^2x + sin^2x)]`

= `[(1, 1),(1, 1)]`   ...[∵ sin²x + cos²x = 1]