Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
Out of given triplets, which is not a Pythagoras triplet?
पर्याय
(9, 40, 41)
(11, 60, 61)
(6, 14, 15)
(6, 8, 10)
Advertisements
उत्तर
(6, 14, 15)
Here, 152 = 225
62 + 142 = 36 + 196 = 232
∴ 152 ≠ 62 + 142
The square of the largest number is not equal to the sum of the squares of the other two numbers.
∴(6, 14, 15) is not a Pythagoras triplet.
APPEARS IN
संबंधित प्रश्न
Adjacent sides of a parallelogram are 11 cm and 17 cm. If the length of one of its diagonal is 26 cm, find the length of the other.
In ∆ABC, point M is the midpoint of side BC. If, AB2 + AC2 = 290 cm2, AM = 8 cm, find BC.

Out of the following, which is the Pythagorean triplet?
Some question and their alternative answer are given. Select the correct alternative.
In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
Do sides 7 cm, 24 cm, 25 cm form a right angled triangle ? Give reason
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.
Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.
Sum of the squares of adjacent sides of a parallelogram is 130 sq.cm and length of one of its diagonals is 14 cm. Find the length of the other diagonal.
Seg PM is a median of ∆PQR. If PQ = 40, PR = 42 and PM = 29, find QR.
If hypotenuse of a right angled triangle is 5 cm, find the radius of
the circle passing through all vertices of the triangle.
Choose the correct alternative:
Out of the following which is a Pythagorean triplet?
In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR.

In ΔABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, then find the length of AP.
Height and base of a right angled triangle are 24 cm and 18 cm. Find the length of its hypotenus?
"The diagonals bisect each other at right angles." In which of the following quadrilaterals is the given property observed?
Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?
In the given figure, triangle ABC is a right-angled at B. D is the mid-point of side BC. Prove that AC2 = 4AD2 – 3AB2.

