Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
Out of given triplets, which is not a Pythagoras triplet?
पर्याय
(9, 40, 41)
(11, 60, 61)
(6, 14, 15)
(6, 8, 10)
Advertisements
उत्तर
(6, 14, 15)
Here, 152 = 225
62 + 142 = 36 + 196 = 232
∴ 152 ≠ 62 + 142
The square of the largest number is not equal to the sum of the squares of the other two numbers.
∴(6, 14, 15) is not a Pythagoras triplet.
APPEARS IN
संबंधित प्रश्न
In ∆ABC, point M is the midpoint of side BC. If, AB2 + AC2 = 290 cm2, AM = 8 cm, find BC.
Out of the following, which is the Pythagorean triplet?
Some question and their alternative answer are given.
In a right-angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?
Find the perimeter of a square if its diagonal is `10sqrt2` cm:
Height and base of a right angled triangle are 24 cm and 18 cm find the length of its hypotenuse
Do sides 7 cm, 24 cm, 25 cm form a right angled triangle ? Give reason
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm then find RS and ST.
In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.
Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.
Sum of the squares of adjacent sides of a parallelogram is 130 sq.cm and length of one of its diagonals is 14 cm. Find the length of the other diagonal.
If hypotenuse of a right angled triangle is 5 cm, find the radius of
the circle passing through all vertices of the triangle.
In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR.
Choose the correct alternative:
Out of given triplets, which is not a Pythagoras triplet?
Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?
In the given figure, triangle ABC is a right-angled at B. D is the mid-point of side BC. Prove that AC2 = 4AD2 – 3AB2.
