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Choose the correct alternative. If elasticity of demand η = 1, then demand is - Mathematics and Statistics

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प्रश्न

Choose the correct alternative.

If elasticity of demand η = 1, then demand is

पर्याय

  • constant

  • inelastic

  • unitary elastic

  • elastic

MCQ
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उत्तर

unitary elastic

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Applications of Derivatives - Miscellaneous Exercise 4 [पृष्ठ ११३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 4 Applications of Derivatives
Miscellaneous Exercise 4 | Q 1.3 | पृष्ठ ११३

संबंधित प्रश्‍न

Find the derivative of the following function from first principle.

`1/x^2`


Find the derivative of the following function from first principle:

−x


Find the derivative of the following function from first principle: 

sin (x + 1)


Find the equation of tangent and normal to the curve at the given points on it.

y = 3x2 - x + 1 at (1, 3)


Find the equation of tangent and normal to the curve at the given points on it.

2x2 + 3y2 = 5 at (1, 1)


Find the equation of tangent and normal to the curve at the given points on it.

x2 + y2 + xy = 3 at (1, 1)


Find the equations of tangent and normal to the curve y = 3x2 - 3x - 5 where the tangent is parallel to the line 3x − y + 1 = 0.


Choose the correct alternative.

If f(x) = 3x3 - 9x2 - 27x + 15 then


Fill in the blank:

If f(x) = `7/"x" - 3`, x ∈ R x ≠ 0 then f ''(x) is ______


State whether the following statement is True or False:

The equation of tangent to the curve y = 4xex at `(-1, (- 4)/"e")` is ye + 4 = 0


State whether the following statement is True or False:

x + 10y + 21 = 0 is the equation of normal to the curve y = 3x2 + 4x - 5 at (1, 2).


Find the equation of tangent and normal to the following curve.

xy = c2 at `("ct", "c"/"t")` where t is parameter.


Find the equation of tangent and normal to the following curve.

y = x2 + 4x at the point whose ordinate is -3.


Find the equation of tangent and normal to the following curve.

y = x3 - x2 - 1 at the point whose abscissa is -2.


Find the equation of normal to the curve y = `sqrt(x - 3)` which is perpendicular to the line 6x + 3y – 4 = 0.


The slope of the tangent to the curve y = x3 – x2 – 1 at the point whose abscissa is – 2, is ______.


Choose the correct alternative:

Slope of the normal to the curve 2x2 + 3y2 = 5 at the point (1, 1) on it is 


The slope of the tangent to the curve x = `1/"t"`, y = `"t" - 1/"t"`, at t = 2 is ______


State whether the following statement is True or False:

The equation of tangent to the curve y = x2 + 4x + 1 at (– 1, – 2) is 2x – y = 0 


Find the equation of tangent to the curve x2 + y2 = 5, where the tangent is parallel to the line 2x – y + 1 = 0


Find the equation of tangent to the curve y = x2 + 4x at the point whose ordinate is – 3


Slope of the tangent to the curve y = 6 – x2 at (2, 2) is ______.


Find the equation of tangent and normal to the curve y = x2 + 5 where the tangent is parallel to the line 4x – y + 1 = 0.


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