Question

Calculate the total number of tetrahedral and octahedral voids formed in 0.6 mol of a compound if it forms hcp structure.

पर्याय

• 3.613 ×10²⁴

• 7.226 ×10²⁴

• 1.084 × 10²⁴

• 2.913 × 10²⁴

Answer 1

1.084 × 10²⁴

Explanation:

Number of atoms in 0.6 mol

= 0.6 × 6.022 × 10²³ atoms

= 3.6132 × 10 atoms

Number of octahedral voids

= Number of atoms

= 3.6132 × 10²³

Number of tetrahedral voids

= 2 × Number of atoms

= 2 × 3.6132 × 10²³

= 72264 × 10²³

Total number of tetrahedral and octahedral voids

= 7.2264 × 10²³ + 3.6132 × 10²³

= 10.8396 × 10²³ ≈ 1.084 × 10²⁴