हिंदी

Calculate the total number of tetrahedral and octahedral voids formed in 0.6 mol of a compound if it forms hcp structure.

Advertisements
Advertisements

प्रश्न

Calculate the total number of tetrahedral and octahedral voids formed in 0.6 mol of a compound if it forms hcp structure.

विकल्प

  • 3.613 ×1024

  • 7.226 ×1024

  • 1.084 × 1024

  • 2.913 × 1024

MCQ
Advertisements

उत्तर

1.084 × 1024

Explanation:

Number of atoms in 0.6 mol

= 0.6 × 6.022 × 1023 atoms

= 3.6132 × 10 atoms

Number of octahedral voids

= Number of atoms

= 3.6132 × 1023

Number of tetrahedral voids

= 2 × Number of atoms

= 2 × 3.6132 × 1023

= 72264 × 1023

Total number of tetrahedral and octahedral voids

= 7.2264 × 1023 + 3.6132 × 1023

= 10.8396 × 1023 ≈ 1.084 × 1024

shaalaa.com
Packing of Particles in Crystal Lattice
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×