Advertisements
Advertisements
प्रश्न
Calculate the pH of the resultant mixtures: 10 mL of 0.2M Ca(OH)2 + 25 mL of 0.1M HCl.
Advertisements
उत्तर
Moles of `"H"_3"O"^+ = (25 xx 0.1)/1000` = .0025 mol
Moles of `"OH"^(-) = (10 xx 0.2 xx 2)/1000 = .0040 " mol"`
Thus, excess of `"OH"^-` = .0015 mol
`["OH"^(-)] = .0015/(35 xx 10^(-3)) "mol/L" = .0428`
`"pOH" = - log ["OH"]`
= 1.36
pH = 14 - 1.36
= 12.63 (not matched)
संबंधित प्रश्न
The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.
Calculate the pH of the following solution:
2 g of TlOH dissolved in water to give 2 litre of solution.
Calculate the pH of the following solution:
1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.
Answer the following in one sentence:
The pH of a solution is 6.06. Calculate its H+ ion concentration.
Answer the following in one sentence :
Calculate the pH of 0.01 M sulphuric acid.
Calculate the pOH of 10-8 M of HCl.
Following solutions were prepared by mixing different volumes of NaOH of HCl different concentrations.
i. 60 mL `"M"/10` HCl + 40 mL `"M"/10` NaOH
ii. 55 mL `"M"/10` HCl + 45 mL `"M"/10` NaOH
iii. 75 mL `"M"/5` HCl + 25 mL `"M"/5` NaOH
iv. 100 mL `"M"/10` HCl + 100 mL `"M"/10` NaOH
pH of which one of them will be equal to 1?
pH of a saturated solution of Ca(OH)2 is 9. The Solubility product (Ksp) of Ca(OH)2
Acidity of \[\ce{BF3}\] can be explained on the basis of which of the following concepts?
If pKb for CN− at 25°C is 4.7, the pH of 0.5 M aqueous NaCN solution is ______.
Define pH.
Define pOH.
Define pH.
Derive relationship between pH and pOH.
Define pH.
Derive the relation pH + pOH = 14.
Define pOH.
Define pOH.
