Question

Calculate the equivalent resistance between points A and C, as shown in the figure.

Answer 1

Resistances of 2 Ω and 6 Ω are connected in parallel between points B and C.

Let R_p be their equivalent resistance.

\[ \frac{1}{R_{p}}=\frac{1}{2}+\frac{1}{6}=\frac{4}{6}=\frac{2}{3} \text { or } R_{p}=\frac{3}{2}=1.5 \Omega\]

Now, equivalent resistance R_p is in series with 10 Ω resistance. Therefore, the equivalent resistance of the circuit (R_s) is :

\[ \text{R}_{\text{s}}=10+1.5={1 1 . 5} \Omega \]