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प्रश्न
Calculate the concentration of a solution of glucose which is isotonic at the same temperature with a solution of urea containing 6.2 g/L.
संख्यात्मक
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उत्तर
`pi = C_"glucose" * R * T = C_"urea" * R * T` ...(Because R and T are same)
urea = 6.2 g/L
Molar mass of urea = 60 g/mol
`C_"urea" = 6.2/60`
= 0.1033 mol/L
Molar mass of glucose = 180 g/mol
Mass of glucose per litre = 0.1033 × 180
= 18.6 g/L
∴ The concentration of glucose solution that is isotonic with 6.2 g/L urea is 18.6 g/L.
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